(n+3)2=n2+3^2=n2+9

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Solution for (n+3)2=n2+3^2=n2+9 equation: 



(n+3)2=n2+3^2=n2+9

We move all terms to the left:

(n+3)2-(n2+3^2)=0

We multiply parentheses

2n-(n2+3^2)+6=0

We get rid of parentheses

2n-n2+6-3^2=0

We add all the numbers together, and all the variables

-1n^2+2n-3=0

a = -1; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·(-1)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation

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